In SX Microcontrollers, SX/B Compiler and SX-Key Tool, bean wrote:

Guenther,
  The whole idea of using the diode is to drop the voltage so the current goes down. Paul said at 3 volts the SX would draw 175 uA. So that would be 175 uA * 0.6V = 105 uW for the diode and 175 uA * 3.0 V= 525 uW for the SX for a total of 630 uW.
  Without the diode the power would be 275 uA * 3.6 V = 990 uW, so with the diode the circuit uses 36% less power.

  That is how I calculate it anyway. Maybe I'm wrong... No I thought I was wrong once, but I was mistaken ;)

Bean.

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