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>From the database of the PIC you will find, that the input impedance of =
the
ADC-pin is 100 kOhms and the max input voltage is Vdd. You have to divide
the Voltage of your Gel-accu in this way that in no circumstances more th=
an
Vdd can be present at the ADC-pin.
When you load your Gel-accu the voltage can climb up to 15 V DC - so in
minimum a divider 3:1 is necessary, 4:1 will bring you to the save side. =
Due
to the fact that there can be noise/spikes on the loading voltage for the
Gel-accu a RC-Filter can be of help to reduce the influence.

 Solution 1: Simple divider by resistances

 R1 is the resistor from the accu to the ADC pin, R2 the resistor from
ADC-pin to ground.

 Choose R1 10 kOhms, then R2 will be 3448 Ohms, a 1% 3,48 kOhm will give =
you
enough accuracy (max. 1.9% error). If this accuracy is not enough, you ha=
ve
to sort out a handfull of 3,48 kOhm resistors to find one which is nearer=
 to
3.448 kOhms.

 For the AC characteristics the network should be of low impedance at 120=
 Hz
(if you use a 60 hertz AC) or 100 Hz, if you use a 50 Hz AC for loading t=
he
accu.

 The 3 db-point of a lowpass filter is typically f =3D 1/ 2*pi*R*C - in o=
ur
case R is 2.86 kOhms (the value of R1 parallel to R2 parallel to the inpu=
t
impedance of the ADC).

 f should be low against the 120 Hz/100 Hz, so we choose it with 30 Hz. I=
f
we bring this values into the equation the calculated C (parallel to R2) =
has
to be > 1.85 =B5F, choosing 2.2 =B5F.

 The conditions for the =B5C are fulfilled - the loading impedance for th=
e ADC
is low enough to have no problems with the LSB showing (stated in AN689a)=
,
the AC attenuation for 60 Hz is around 12 dB - and we need only 3
components.

 Solution 2: Divider and Voltage follower/filter

 The voltage follower will bring in minimum 2 advantages - transforming o=
f
the input impedance to nearly infinite (which means around 100 MOhms) and
steeper filtering curve (which means better AC=B4/spike attenuation). The
disadvantages are clear: more components, additional offset voltage error=
,
higher cost.

The attached picture will show solution 2.

 Regards

 Enrico




> ----- Original Message -----=20
> From: "fred jones" <boattow@hotmail.com>
> To: <piclist@mit.edu>
> Sent: Tuesday, November 15, 2005 2:08 AM
> Subject: [PIC] How to read Battery voltage with PIC
>
>
> >
> > Hi all,
> > I'm sure this is an easy question for many of you so I hope I don't g=
et
> > flamed.  I searched but can't find the answer in the archives althoug=
h
I'm
> > sure it must be there somewhere.  This is not my strong point so I
thought
> > I'd ask for help.
> >
> > I am building a device that will run off of a 12V gel cell battery.  =
It
> will
> > use a 16F877 PIC powered with a 7805 regulator.  I'd like to be able =
to
> read
> > the voltage of the gel cell and display it on the 2X16 LCD display.  =
I'm
> > sure I can't connect the 12V batter into the A2D of the PIC but I'm n=
ot
> sure
> > what the proper method would be.  Any help is appreciated.
> > Thanks for your time,
> > FJ
> >
> >
> > --=20
> > http://www.piclist.com PIC/SX FAQ & list archive
> > View/change your membership options at
> > http://mailman.mit.edu/mailman/listinfo/piclist
> >
>

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