Olin Lathrop wrote:

>Stephen D. Barnes wrote:
>  
>
>>I just want to be sure I really understand what happens here...please
>>correct me if I am wrong.
>>
>>.bss    myvar, 2, 2            ;defines variable, 2 bytes long, aligned
>>    
>>
>
>Yes.
>
>  
>
>>        mov    #myvar, w0      ;move the contents of myvar to w0
>>    
>>
>
>No, it write the address of MYVAR into W0.  In other words, W0 is not a
>pointer to MYVAR.
>
>  
>
>>        mov.b  [w0++], w1      ;move 1 byte of w0 to w1(low byte)
>>and
>>post increment the                                        ;"effective
>>address" which means the w0 low byte will now contain
>>               ;what was the high byte before the increment?
>>    
>>
>
>The instructions are all detailed in the manual.  Since you're just asking
>about details of the instruction operation, you should read the manual.
>Briefly, this fetches the byte pointed to by W0, sticks it in the low half
>of W1, then increments W0 by 1.
>
>
>******************************************************************
>Embed Inc, Littleton Massachusetts, (978) 742-9014.  #1 PIC
>consultant in 2004 program year.  http://www.embedinc.com/products
>  
>
I am reading the dsPIC30F family reference, dsPIC30F2010 datasheet, and 
the dsPIC30F programmers reference.
In some cases I have had to search the documents for things such as the 
[w0++] and bouncing back and forth to piece together my understanding of 
the code snippets you posted. Thanks for the clarification....and today 
I will sit down and read the prog ref
in an orderly fashion!

-- 
Regards,
Stephen D. Barnes

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