Stephen D. Barnes wrote:
> I just want to be sure I really understand what happens here...please
> correct me if I am wrong.
>
> .bss    myvar, 2, 2            ;defines variable, 2 bytes long, aligned

Yes.

>         mov    #myvar, w0      ;move the contents of myvar to w0

No, it write the address of MYVAR into W0.  In other words, W0 is not a
pointer to MYVAR.

>         mov.b  [w0++], w1      ;move 1 byte of w0 to w1(low byte)
> and
> post increment the                                        ;"effective
> address" which means the w0 low byte will now contain
>                ;what was the high byte before the increment?

The instructions are all detailed in the manual.  Since you're just asking
about details of the instruction operation, you should read the manual.
Briefly, this fetches the byte pointed to by W0, sticks it in the low half
of W1, then increments W0 by 1.


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