Hi, I'm trying to tweak the resistor values in an intensity/focus chain for a CRT. The circuit ATM looks like this ('scuse the ascii art): 47k 20k 82k 100k 940k (2x470k) -600V <<<---/\/\/---/\/\/---*----/\/\/---/\/\/------/\/\/-----> 0V ^ | ^ | | | | | | | | | Vg1 (inten) Vk (cathode) Vg3 (focus) Now, this looks to me like two potential dividers, which combine to make one potential divider and two "sub-dividers" if that makes any sense. If I change the total resistance on one side, the other side will be affected and vice versa. So how do I pick resistor values for this thing? Here's how I simplified/understood it: 67k 1122k -600V <<<---/\/\/----*----/\/\/-----> 0V | | Vk At the moment, this circuit's outputs are (assuming my maths is correct): Vg1: -600V to -574V Vk: -564V fixed Vg3: -522V to -492V What I need is: Vg1: -600V to -550V Vk: -500V fixed Vg3: -500V to -380V So how should I go about modifying this circuit? So far this is the best way I've come up with: 1- Work out the values for the simplified circuit, so that Vk = -500V for R1+R2=1Meg2. New R1=x, new R2=y. 2- Split the circuit down into two dividers. 3- Calculate the component values required for the Vg1 divider, with R1+R2=x 4- Calculate the component values required for the Vg3 divider, with R1+R2=y Does this sound like it'll work? Thanks, -- Phil. | Acorn RiscPC600 SA220 64MB+6GB 100baseT philpem@philpem.me.uk | Athlon64 3200+ A8VDeluxe R2 512MB+100GB http://www.philpem.me.uk/ | Panasonic CF-25 Mk.2 Toughbook Beware of programmers who carry screwdrivers. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist