> How would you calculate e^(-at) in 32 bit integer math?
> 
> Why does it need to be integer math?  From your previous post 
> I got the impression this calculation was going to be done at 
> assembly time.

The assembler I'm using only supports integer math. No fractions. No
floating point. Just integers. So if you put in .36 it becomes 0. 92/256 =
0. Integer math.

How do you calculate e^(-x) where x is between 1/256 and 192/256 using only
integer math.

---
James.
 

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