> > One
> > thing I noticed in the schematic is that the Vdd to the device being
> > programmed is taken directly from the USB port's +5. This
> > being  the case, I
> > wonder how it manages the PICs with a Vpp-before-Vdd programming
> > requirement?
>
> And how will it cope with an USB to outputs the minimum voltage allowed
> by USB specs (IIRC < 4.5V)?
>

Yeah, and take a look at the kludge of a charge pump for Vpp. Looks like a
recipie for disaster to me.

-Denny

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