Russell,

On Thu, 08 Sep 2005 21:46:50 +1200, Russell McMahon wrote:

> >> Solar insolation / day is about 1.3 kWh/m^2 x disc area in m^2 x 24 
> >> hrs/day kWh
> 
> > Errr - hang on, that fails dimensional analysis!  You can't have kWh 
> > at both ends and also multipy by 24hrs...
> > Do you mean 1.3kW/m^2 ?
> 
> Well, I was being sloppy - I meant 1.3 kWh/h/m^2, which of course is 
> 1.3 kW, but one is power and the other energy :-).

OK, sorted!
 
> > ... and if so, I don't think anywhere on Earth gets this much for 
> > 24hrs/day :-).
> 
> Oh, it does.
> It's falls on projected stationary earth sized disc I used in my 
> calculation.

Right, but where would you build this - and if we towed it behind the Earth, how would we connect the power 
cable?  :-)

I was thinking more practically, less theoretically...

And to finish on a pedantic note: "Solar insolation" is a tautology!  :-)))

Cheers,



Howard Winter
St.Albans, England


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