On Thu, Aug 25, 2005 at 12:48:41PM -0500, Mark Rages wrote:
>
> That's a clever method, but you should probably measure the 4700uF
> cap's actual capacitance. (electrolytic caps can vary by a lot).  Use
> the same method, but substitute a high-value 1% resistor instead of
> the test circuit.  Solve for C instead of I.

A very good idea Mark! The cap I'm using has a +-20% tolerance.

Matthew

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