Hi Dave/Neil, That should do it...my mistake, and there's me cursing Linux. This is going to be Fun... Thank you both for the help, is the little things that always get in the way of the big ones. Best regards Luis Luis Moreira luis.moreira@jet.uk tel. 01235464615 JET PSU Department UKAEA Culham Division J20/1/55, Culham Science Centre Abingdon Oxfordshire OX14 3DB -----Original Message----- From: piclist-bounces@mit.edu [mailto:piclist-bounces@mit.edu] On Behalf Of Neil Thompson Sent: 15 July 2005 09:18 To: piclist@mit.edu Subject: Re: [OT]: LINUX On Fri, Jul 15, 2005 at 08:40:42AM +0100, Luis Moreira wrote: > > setup my email by giving it the incoming and outgoing servers. In my > case they are POP3@blueyonder.co.uk and SMTP@blueyonder.co.uk . I think you'll find that the server names are pop3.blueyonder.co.uk and smtp.blueyonder.co.uk respectively (i.e. lose the @ sign). Just make sure that you can resolve the names on your machine by opening a terminal session and using the "dig" command (e.g. dig pop3.blueyonder.co.uk). If there are errors resolving the names, you won't be able to connect to them. Also, make sure that you can get through to the servers, by firstly pinging them, and then by trying to telnet to them on the pop3 and smtp ports. -- Cheers! (Relax...have a homebrew) Neil THEOREM: VI is perfect. PROOF: VI in roman numerals is 6. The natural numbers < 6 which divide 6 are 1, 2, and 3. 1+2+3 = 6. So 6 is a perfect number. Therefore, VI is perfect. QED -- Arthur Tateishi -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist