On 7/14/05, Marcel Birthelmer <marcel@carrietech.com> wrote:
> Marcel Birthelmer wrote:
> >> A = - (1-j*omega* Rv*C)/(1+j*omega*Rv*C) where omega is 2*pi*f
> >>The phase shift will be:
> >>Fi = -2*tan^ -1 (omega*Rv*C) - 180
> >>so the phase shift will be between -180 to -360 degree
> >>
> >>best regards,
> >>Vasile
> >>
> >>
> >
> >
> > Vasile,
> > thanks for your answer. After some equation-crunching (also with the
> > help of Olin), I came up with the same Gain equation you have. However,
> > I'm afraid I don't understand how to get the phase shift from that. I
> > assumed that simply finding the argument (arctan(Im/Re)) would be
> > enough, but that gives me a range from 0 to 360
> 
> EDIT: 0 to Pi. 180. I'm an idiot.

 Not too sure. An idiot can't compute the thing you've did.
:)
 The - sign is a matter of inversion. To change the phase between in
the 0-180 range just replace your resistor with your capacitor on the
positive branch of the OA.

nice computing time,
Vasile

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