Marcel Birthelmer wrote:
>> A = - (1-j*omega* Rv*C)/(1+j*omega*Rv*C) where omega is 2*pi*f
>>The phase shift will be:
>>Fi = -2*tan^ -1 (omega*Rv*C) - 180
>>so the phase shift will be between -180 to -360 degree
>>
>>best regards,
>>Vasile
>>
>>
> 
> 
> Vasile,
> thanks for your answer. After some equation-crunching (also with the
> help of Olin), I came up with the same Gain equation you have. However,
> I'm afraid I don't understand how to get the phase shift from that. I
> assumed that simply finding the argument (arctan(Im/Re)) would be
> enough, but that gives me a range from 0 to 360 

EDIT: 0 to Pi. 180. I'm an idiot.

which obviously isn't
> right. (I'm using Maple 9 for the actual evaluation and plotting with
> different frequencies and resistor values.)
> Any ideas?
> - Marcel

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