>  A = - (1-j*omega* Rv*C)/(1+j*omega*Rv*C) where omega is 2*pi*f
> The phase shift will be:
> Fi = -2*tan^ -1 (omega*Rv*C) - 180
> so the phase shift will be between -180 to -360 degree
> 
> best regards,
> Vasile
> 
> 

Vasile,
thanks for your answer. After some equation-crunching (also with the
help of Olin), I came up with the same Gain equation you have. However,
I'm afraid I don't understand how to get the phase shift from that. I
assumed that simply finding the argument (arctan(Im/Re)) would be
enough, but that gives me a range from 0 to 360 which obviously isn't
right. (I'm using Maple 9 for the actual evaluation and plotting with
different frequencies and resistor values.)
Any ideas?
- Marcel
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