On 7/10/05, Marcel Birthelmer wrote: > Hi all, > apologies for the n00b-ness of my question but being a first-year EE > student I haven't learned enough useful things yet to figure out the > workings of the following circuit: > > http://marcel.carrietech.com/phase.png This is a wrong drawing, as it's will be an oscillator, change the +input with -input on the OA. Then the gain will be: A = - (1-j*omega* Rv*C)/(1+j*omega*Rv*C) where omega is 2*pi*f The phase shift will be: Fi = -2*tan^ -1 (omega*Rv*C) - 180 so the phase shift will be between -180 to -360 degree best regards, Vasile > > This is a phase shifting circuit (Rv being variable) that I found > online. Could someone please explain how to calculate the output voltage > given the input voltage and the various components? I've checked all my > EE books (which are all intro level, unfortunately) and have come up dry. > Thanks, > - Marcel > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist