THANKS for all the responses! I used:

SongArray= Song1Array;      // direct pointer assignment

and it worked great.

THANKS!

Harold


> Harold Hallikainen wrote:
>> main.c:369:Error
>> [1131] type mismatch in assignment
> [...]
>> SongArray=&Song1Array;
>
>>>> struct SongChord rom const Song1Array[]={ data goes here }
> [...]
>>>> struct SongChord rom const *SongArray;  // local pointer to a
>>>> song
> [...]
>>>> SongArray=&Song1Array;
>
> Song1Array is defined as an array of SongChord structs.
>
> The subscript operator is just a clever(?) syntactical trick to hide the
> pointer arithmetic behind arrays in c.
>
>  SongArray               =  &            Song1Array
> (pointer to a SongArray) = (address of) (pointer to 1st SongArray)
>
> Either of the following will work (choose the one that makes the most
> sense to you):
>
>   SongArray= Song1Array;      // direct pointer assignment
>   SongArray= &Song1Array[0];  // address of dereferenced pointer
>
>   You can also write the above statement like this ( the "+ 0" is to
> help clarify the comparison).
>
>   SongArray= & *(Song1Array + 0);
>
> HTH,
> Tad Anhalt
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