Harold Hallikainen wrote:
> C:\ProductDesigns\HuwaldtGuitar\Control\050415\main.c:369:Error 
> [1131] type mismatch in assignment
[...]
> SongArray=&Song1Array;

>>> struct SongChord rom const Song1Array[]={ data goes here }
[...]
>>> struct SongChord rom const *SongArray;  // local pointer to a 
>>> song
[...]
>>> SongArray=&Song1Array;

Song1Array is defined as an array of SongChord structs.

The subscript operator is just a clever(?) syntactical trick to hide the
pointer arithmetic behind arrays in c.

 SongArray               =  &            Song1Array
(pointer to a SongArray) = (address of) (pointer to 1st SongArray)
	
Either of the following will work (choose the one that makes the most
sense to you):

  SongArray= Song1Array;      // direct pointer assignment
  SongArray= &Song1Array[0];  // address of dereferenced pointer

  You can also write the above statement like this ( the "+ 0" is to
help clarify the comparison).

  SongArray= & *(Song1Array + 0);

HTH,
Tad Anhalt
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