Dave Turner wrote:
> BTW, does anyone know how fast it can send letters, i.e. how many
> processor cycles between sending letters?

You can figure this out yourself.  Assuming you are using "normal" protocol,
there is a start bit, 8 data bits, and a stop bit per byte sent.  That makes
a total of 10 bits.  At 9600 baud you can transmit 960 bytes/second at
maximum rate.  At 8MHz oscillator you get 2MHz instruction rate.  (2M
cycles/sec) / (bytes/sec) = 2083 instructions per byte.


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