Nathanial Hendler <equant@retards.org> wrote:
> So then which value of j is used in the definition of l?
>
> l = i - j
>
> Any ideas?

The last one.
Solve the equations sequentially, or 
rename the variables and reassign the
names.


Try this in basic:
INPUT "Given year: ", y
c = CINT(y / 100)
n = y - (19 * INT(y / 19))
k = INT((c - 17) / 25)
i = c - INT(c / 4) - INT((c - k) / 3) + 19 * n + 15
i = i - 30 * INT(i / 30)
i = i - INT(i / 28) * (1 - INT(i / 28) * INT(29 / (i + 1)) * INT((21 - n) /
11))
j = y + INT(y / 4) + i + 2 - c + INT(c / 4)
j = j - 7 * INT(j / 7)
l = i - j
m = 3 + INT((l + 40) / 44)
d = l + 28 - 31 * INT(m / 4)

PRINT m
PRINT d

reassigned version ("c like"):
y=2010
c=floor(y/100)
n=y-19*floor(y/19)
k=floor((c-17)/25)
i=c-floor(c/4)-floor((c-k)/3)+19*n+15
z=i-30*floor(i/30)
w=z-floor(z/28)*(1-floor(z/28)*floor(29/(z+1))*floor((21-n)/11))
j=y+floor(y/4)+w+2-c+floor(c/4)
u=j-7*floor(j/7)
l=w-u
m=3+floor((l+40)/44)
d=l+28-31*floor(m/4)

floor means int, in "Derive" syntaxis.

Dennis Crawley
Argentina




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