> "Wouter van Ooijen" writes:
>>The suggestion was to put a diode in series with the lamp. No 
>>capacitors
>>(or inductors or other storage elements). You want to say that this
>>istuation the energy in half the sine (say positive halve only) is 
>>0.7
>>times the energy in the full sine? So the energy in the positive + 
>>the
>>negative halves must be 1.4 the energy in the full sine ???? I think 
>>you
>>should apply for a patent immediately!

> A resistive load like a light bulb should burn almost the same
> brightness when placed at the output of an unfiltered bridge as it
> does when it is directly across the line.

A single diode supplying half wave will give the filament time to cool 
for substantially longer. Bulb filaments have time constants which are 
roughly in the order of a half cycle - ie they do give mains hum when 
a photodetector is used with them but do not give deep flickering on 
the half cycles. So you would expect a reasonably greater degree of 
cooling when left off for a whole half-cycle.

A warm filament has a higher on resistance than a colder filament so 
MAYBE one might expect half cycle AC to give MORE than half the watts 
of full cycle AC :-)




        RM

-- 
http://www.piclist.com PIC/SX FAQ & list archive
View/change your membership options at
http://mailman.mit.edu/mailman/listinfo/piclist