Padu wrote :

> 10 ms is for one timeslot only. So portc:0 sends its pulse in 
> timeslot 'A'.  portc:1 sends its pulse in the next timeslot.
> When it's the timeslot 'A' again, 20ms have passed by,
> therefore the dutycycle is correct. As I stated in another
> message, if the angles are dictated from a calculated number
> by the PIC itself, the movement is very smooth (like a swiss 
> clock), but if the angles are sent from a PC using RS232,
> then it gets rough...

Note that 10ms (or even 1 ms) is a rather long time for a PIC.
Usualy timers are best to "time" those intervals, not software
delay loops. (I'm not sure if and, if so, how much timers was
used in your code...)

B.t.w, you mentioned 4 Mhz, but did you mention the PIC model ?

Jan-Erik.



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