Can anyone suggest practical means to use a hardware division function for 
greater precision division? eg 8/8 divide extended to 16/16 etc.
(A friend says it can't readily be done.)

Extending hardware multiplication is trivial as AB x D = BD + base.AD
(where A x base = A0)

Extension of division where only the dividend is increased in size works OK

    AB/C = A.base/C + B/C

But division where the divisor is extended does is not instantly obvious (to 
me).

eg    AB/CD = A.base/CD  + B/CD
    But eg B/CD is trickier.

Musing

B/CD = xD/CD + yC/CD= x/C + y/D
xC + yD = B

Playing with this doesn't seem to get me anywhere.
Any thoughts?


        Russell McMahon







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