return takes 2 also.

Jianhua Zhang wrote:
> I have a small delay subroutine in my code:
> 
> .....
> call	delay
> ....
> 
> delay
> 	nop
> 	nop
> 	nop
> 	return
> 
> Now I want to replace the 'call delay' with some 'nop's.
> How many 'nop' should I use so the program will run same time as the 'call
> delay'? I know a 'call' equals 2 'nop's. what about the 'return'?
> 
> 
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