Hello to you
Using the delay generator from
I have generated 21 different delay routines. (I need these for different
LED flash sequences). The question is: do I need to define 21 different
temporary registers in CBLOCK? i.e. see below please. What is $+2? In the
manual it says return program counter (see my comment beside the code line)
I appreciate your input & advice on this one ;-)
Regards


CBLOCK 0x20   ; RAM starts at address 20h
D1
D2
D3
.
.
.
D21
ENDC

Follwoing are the two example and then the third one is that I merge them.
; Delay = 0.2 seconds
        cblock
        d1
        d2
        endc

                        ;199998 cycles
        movlw   0x3F
        movwf   d1
        movlw   0x9D
        movwf   d2
Delay_0
        decfsz  d1, f
        goto    $+2             ; Does this mean go two lines back (delay_0)?
        decfsz  d2, f
        goto    Delay_0

                        ;2 cycles
        goto    $+1

; Delay = 0.4 seconds
        cblock
        d1
        d2
        d3
        endc

                        ;399999 cycles
        movlw   0x36
        movwf   d1
        movlw   0xE0
        movwf   d2
        movlw   0x01
        movwf   d3
Delay_0
        decfsz  d1, f
        goto    $+2
        decfsz  d2, f
        goto    $+2
        decfsz  d3, f
        goto    Delay_0

                        ;1 cycle
        nop

; delay for 0.2 and 0.4 can I call form this code upon delay 0.2s or ; ;
0.4s or if I add more into it

        cblock
        d1
        d2
        d3
        d4
        d5

        endc

delay_0.2s              ;199998 cycles
        movlw   0x3F
        movwf   d1
        movlw   0x9D
        movwf   d2
Delay_0.2               ; note 0.2 and 0.2s
        decfsz  d1, f
        goto    $+2
        decfsz  d2, f
        goto    Delay_0.2

                        ;2 cycles
        goto    $+1

delay_0.4s                      ;399999 cycles
        movlw   0x36
        movwf   d3
        movlw   0xE0
        movwf   d4
        movlw   0x01
        movwf   d5
Delay_0.4
        decfsz  d3, f
        goto    $+2
        decfsz  d4, f
        goto    $+2
        decfsz  d5, f
        goto    Delay_0.4

                        ;1 cycle
        nop

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