Ask an analog question in a digital group...! Assuming there's power on both sides of the circuit, use an opamp on one side to light the LED inside the optocoupler. The brightness will depend on the current flow, which will depend on the output of the opamp, which will depend on the signal. On the transistor side, measure the current flowing through the transistor in the optocoupler. Use an opamp to buffer it and convert it back to a voltage. Pick the correct values for the opamp gains and the voltage out will equal the voltage in over the entire range. Pick the correct opto and opamps and you will get all the bandwidth you could ever use. Maximum of one tiny opamp on each side, an opto, and maybe 5-10 passive parts. Bonus points if you use transistors instead of opamps, since they'll be vastly cheaper and an opamp is overkill for this application There are some great circuits that do exactly what you need in this data sheet: http://literature.agilent.com/litweb/pdf/5988-4104EN.pdf Hope this helps! -Adam Jinx wrote: >Any suggestions/recommendations for opto-coupling a DC or low frequency >signal (10s of Hz) to the AN pins for measurement ? Maybe V-F -> F-V for >example ? Pointers to a proven design would be absolutely spiffing > >TIA > >-- >http://www.piclist.com hint: PICList Posts must start with ONE topic: >[PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads > > >. > > > -- http://www.piclist.com hint: The list server can filter out subtopics (like ads or off topics) for you. See http://www.piclist.com/#topics