Millions thanks for the prompt reply,
Just to digest the information I quickly went through the relevant infos in
the manual.
All the ports will be outputs with the expiation of B (B1 to B3 = input)
following are the comments that I put beside each line
Rgds,
Aslam

dbankif portc    ;Couldn t find this in assembly instruction list
     movf    portc, w ;Got you there NO PROBLEM)
     iorlw   b'00011000' ;inclusive OR means 0 has no effect
     movwf   portc    ;write modified value back to port (Got it)

To clear bits, AND with the appropriate mask:

     dbankif portc    ;Don t get it!
     movf    portc, w ;read the old PORTC value
     andlw   b'11100111' ;got you ANDING with 0 return 0!
     movwf   portc    ;write modified value back





>> > Hi to every one of you every where
> > A Very concrete question: If in the following code I want to clear
> > bit 4 and bit 3 and then call the delay and then set both bit 3 and 4
> > Basically, instead of one pin at the time I want to make two pins
> > high or low  How can I do this? Would simply bcf  PORTC, 4,3 work?
>
>No.  BSF and BCF operate on only one bit at a time.  To change multiple
>bits
>simultaneously, you have to write a new value to the whole port.  To just
>set bits 4 and 3, read the port, OR with the appropriate mask, then write
>the result back to the port:
>
>      dbankif portc    ;make sure banks are set for access to PORTC
>      movf    portc, w ;read the old PORTC value
>      iorlw   b'00011000' ;make sure bits 4 and 3 are 1
>      movwf   portc    ;write modified value back to port
>
>To clear bits, AND with the appropriate mask:
>
>      dbankif portc    ;make sure banks are set for access to PORTC
>      movf    portc, w ;read the old PORTC value
>      andlw   b'11100111' ;make sure bits 4 and 3 are 0
>      movwf   portc    ;write modified value back to port
>
>Beware of the read-modify-write behaviour of I/O ports.  On a read of the
>port register, you get what the pin voltage is, NOT what the output latch
>is
>set to.  These can differ if the pin is an input, or the external circuit
>is
>forcing the pin level.  There is a bit more to this but it's been discussed
>many times here before and is also well documented in the manual.  Make
>sure
>you understand the issue.
>
>
>*****************************************************************
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>(978) 742-9014, http://www.embedinc.com
>
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