On Jul 31, 2004, at 12:09 PM, Peter L. Peres wrote:

> numerically you can solve it by numerical integration. use the line
> that passes through both circle centers as ordinate axis and integrate
> each circle's 'banana' area, on the domain R*cos(A/2) to R, then add
> the two results. A is the center angle that subtends the intersection
> points on the circle, for each circle...

You can almost certainly do this integration symbolicly too, although
it would probably be a moderately unpleasant task even if you were a
3rd year physics student and calculus was still fresh in your mind...

BillW

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