On Fri, Jul 23, 2004 at 09:33:10AM -0400, Bob Ammerman wrote:
>
> This is incorrect. You _cannot_ perform arithmetic on a void *. About the
> only things you can do with a void *  are assign other pointers to them,
> assign them to one another, pass them as arguments, and convert them to a
> pointer to another type.

Bob, thanks for pointing that out.  I was generalizing based on gcc,
which only warns about void pointer arithmetic when -pedantic is
supplied (and still doesn't consider it an error even in ANSI mode).

--
Ryan Underwood, <nemesis@icequake.net>

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