> I was sent
>
> If a = b, then:
>
> a^2 = a*b
>
> a^2 - b^2 = (a*b) - b^2
> (a-b)(a+b) = b(a - b)
>
> (a+b) = b
>
> Substitute the original a = b into the equation:
>
> 2b = b
> 2 = 1

Took a few moments of staring :-)
(a-b)(a+b)=b(a-b)
BUT a=b so
(0)(2a) = b (0)
So either 0 = 0 (correct)

Or 2a=b is required for the 0's to be "the same"
But a=b, so no cigar.


        RM

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