Sorry, Scott I didn't read the second part of your mail.

> I obviously don't have your code, but I think it should take around 32 to
> 34 instructions. The algorithm is something like this:
>
>    t = b;
>
>    t = t + a;
>    t = t>>1;
>
>    t = t + a;
>    t = t>>1;
>
>    t = t + a;
>    t = t>>1;
>
>    a = t + a;
>    a = a>>1;

Done!. It works 32 instrucctions.
     movfw   x0
     addwf   y0,f
     btfsc   STATUS,C
     incf    y1,F
     movfw   x1
     addwf   y1,f
     rrf     y1,f
     rrf     y0,f

     movfw   x0
     addwf   y0,f
     btfsc   STATUS,C
     incf    y1,F
     movfw   x1
     addwf   y1,f
     rrf     y1,f
     rrf     y0,f

     movfw   x0
     addwf   y0,f
     btfsc   STATUS,C
     incf    y1,F
     movfw   x1
     addwf   y1,f
     rrf     y1,f
     rrf     y0,f

     movfw   y0
     addwf   x0,f
     btfsc   STATUS,C
     incf    x1,F
     movfw   y1
     addwf   x1,f
     rrf     x1,f
     rrf     x0,f

I think I forget the clrc!... in case an overflow from the addition occurs.
In that case 36 instructions.

Regards,
Dennis.

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