> Keep in mind that you also MIGHT experience a tiny jitter caused by an
> interrupt occurring between 2-cycle instructions, which are always
> completed before the INT is taken. This tiny error is not accumulative
> so won't affect anything.
>
> --Bob

If you need to, you can 'dejitter' the timing as follows in the interrupt
handler:


    btfsc    TMR0,0
    goto    $+1
A:


If bit 0 of the timer is set, this code takes 3 cycles, if not it takes two
cycles, this you always give to point "A" when the timer has the same value.
(Actually this is a simplification, you may need to use a btfss instead of a
btfsc, I am too lazy to figure out which right now).

Bob Ammerman
RAm Systems

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