> Hmm, this may not work for this situation if both PICs > are on the same power > supply, unless you slug the MCLR line of one with a > larger capacitor than the other. I'm assuming that the slave can't initiate transmission. If that is the case, the PIC that starts up and sees the TX hi/RX low combination is the master. The master then sets the designated pin ("slave ready to receive" pin) as input and waits for a change in state. This allows the other PIC to see TX lo/RX hi and become the slave. Once it knows it's the slave, it changes the designated pin ("slave ready to receive") to output and changes state. Doesn't that always work, regardless of which PIC starts first? I was just trying to find out if it was the "best" way to do it. -- http://www.piclist.com hint: To leave the PICList mailto:piclist-unsubscribe-request@mitvma.mit.edu