I looked at the data sheet you mentioned, and it showed the LEDs coming out with both leads. I had one display that had only the anode brought out, but it only drew about 40 ma, so it was easy to use a single transistor to drive the backlight form 5V. At 02:33 AM 3/26/2004 +0100, you wrote: > > Note that you have access to both the anode and > > cathode of the backlight, so you can connect the anode to the +9 volts, > > then connect the cathode via a resistor to the FET. You don't have to drive > > the anode of the LED, trying to switch 9 volts. That's why you need to use > > 2 transistors in your circuit. > >I'll try to use the FET. The problem is I'm not sure if the cathode of the LED >is connected to the LCD's VSS. > >I recently used 1 NPN transistor to do it this way (but with other display). >When I plugged it everything started getting hot. After some testing I >found that >VSS and the LED's cathode were connected in the LCD's pcb. A *little* fact the >datasheets didn't mention. > > >Thanks for the responses! > >-- >http://www.piclist.com hint: To leave the PICList >mailto:piclist-unsubscribe-request@mitvma.mit.edu Larry Bradley Orleans (Ottawa), Ontario, CANADA -- http://www.piclist.com hint: To leave the PICList mailto:piclist-unsubscribe-request@mitvma.mit.edu