> Note that you have access to both the anode and
> cathode of the backlight, so you can connect the anode to the +9 volts,
> then connect the cathode via a resistor to the FET. You don't have to drive
> the anode of the LED, trying to switch 9 volts. That's why you need to use
> 2 transistors in your circuit.

I'll try to use the FET. The problem is I'm not sure if the cathode of the LED
is connected to the LCD's VSS.

I recently used 1 NPN transistor to do it this way (but with other display).
When I plugged it everything started getting hot. After some testing I found that
VSS and the LED's cathode were connected in the LCD's pcb. A *little* fact the
datasheets didn't mention.


Thanks for the responses!

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