As part of a simulation of received data, I'm copying a text block
from flash to RAM, then searching it for strings. There are 6 blocks
of 150-odd bytes, each stored at 0x2800 + X*0x100, where X is
block number 0 to 5 inclusive

I'm not clear exactly how = works. It does, because I get what
I wanted. Looking at txt_add in a Watch Window shows the
address 2800 and the value 0007. txt_add is not mentioned
in CBLOCK or anywhere else, only in this statement below.

Address 2800 in Program Memory still shows the ASCII char
"54" that was loaded with the .hex file, RAM location 0007 is 00

Anybody know ? Not overly important, just curious. Is it a "virtual"
value that can't be seen directly ?

=================

txt_add=0x002800                ;text base address

         clrf    tab_os         ;table offset, add to source base address

copy_x   lfsr    fsr0,0x100     ;target RAM address

         movlw   upper(txt_add) ;source base address, 0x002800
         movwf   tblptru

         movfw   tab_os         ;add X * 0x100 block offset
         addlw   high(txt_add)
         movwf   tblptrh

         movlw   low(txt_add)
         movwf   tblptrl
         incf    tab_os         ;increment for next block copy

;do copy

==============================================
Research is what I'm doing when I don't know what I'm doing
- Wernher von Braun

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