At 00.42 06/03/2004 +0200, you wrote:
>> Something has always puzzled me about light - if Einstein is right, how
>> can it exhibit Doppler shift?  As I
>
>The energy of a light particle (photon) is h*mu where mu is frequecy in
>Hx. If Einstein is right them E=m*c^2 is constant for the photon in free
>space and then:
>
>        h*mu = m*c^2
>
>But if you move wrt. the origin c is not c-v where v is your speed (or the
>speed of the origin), and:
>
>        h*mu = m*(c-v)^2
>
>Since h, n, c, and v are constants (you are saying you know v, aren't you
>?), the only thing left to change to fix the equation is mu, but mu is the
>frequency. So mu (the frequency, aka 1/wavelength, aka redshift) decreases
>when the observer travels away from the source of light (or the source of
>light travels away from the observer) (remember light energy is a vector
>so vector addition applies between c, the speed of the photon, and v, the
>speed of the source/your speed - that's how you get blueshift, or
>increased frequency - by traveling towards the source).
>
>Peter

Very interesting stuff. By the way, would a stream of electrons moving at
about 1/20th of the speed of light (which if I made my calculations right
means a wavelength of about 500 nM) produce visible, green light, when
approaching an eye or an optical sensor?

If not, why?

Greets,
Andrea

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