Putting + voltage directly on the base without much current limiting (resistor in series) will blow the base emitter junction. The base acts like a single diode and has 0.7 volts drop. Thus it will draw almost the short circuit current of the +12V supply. Put a 1k resistor in series with the +12V to prevent damage. Putting - voltage on the base (again without current limiting) will cause the base emitter junction to act as a zener diode, and also blow the junction. The junction should "zener" at about negative 6 - 8 volts? Check this by putting a 1K in series with the -12V. If you can put +/- 12V directly on the base with very little current flow, the base-emitter junction is already blown open. Transistors are CURRENT operated devices. The collector to emitter current is controlled by base to emitter current (Beta=Ic/Ib= 50-400?). You always have resistors or some way to limit the currents that result from applying the voltages. The "Diode" function on a DMM is a good way check to see if you still have a B-E junction. Usually the RED lead is + on a DMM? Reverse the leads to make sure there is no reverse conduction. You can also use the +12V PS with the 1K series resistor and measure the B-E voltage with the DMM. Again, flip the voltage around to check the "Zener" effect. Transistors are cheap, so that is the good news! -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads