Would not used a wire wound resistor as this will be an inductor that my
cause incorrect readings.

*************************************************
Roy Hopkins   :-)

Tauranga
New Zealand
*************************************************

----- Original Message -----
From: "Ian McLean" <ianmm@OPTUSNET.COM.AU>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Saturday, February 21, 2004 3:52 AM
Subject: Re: [EE:] Current Transformers


> Yes, thanks Bob.  I am aware now of this danger.  I can understand this
> considering the turns ratio - 1 to, ummm... a lot.  I will be sure to well
> and trully overrate the burden resistor's wattage rating.  If I use a 50:5
> CT, then at 5A max. on CT secondary, and using, say a 0.1 ohm burden
> resistor, the dissipation is I2R = 5^2 * 0.1 = 2.5W.  I'll go with a 10W
> rated wire wound resistor to be safe.  Sound reasonable ? I believe the
TSV
> diode will provide me some protection as well. Then the max. voltage
across
> this burden resistor = IR = 5 * 0.1 = 0.5V.  If I use an op-amp with 10
> times gain, and clipping at 5V (to protect PIC A/D input), then along with
> the TSV that should provide me with about as much protection as possible,
> yes ?
>
> BTW: This is for AC mains (240VAC, 50Hz) current measurement in an AC
> control box (variac controlled) to power a Tesla Coil.  The mains at 12kW
> max. input is powering a 15,000VAC transformer, which in turn gets stepped
> up on the coil to well over 600,000VAC at about 140kHz, so ... big,
> dangerous voltages everywhere here to worry about ;)
>
> Rgs
> Ian
>
> > -----Original Message-----
> > From: pic microcontroller discussion list
> > [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Bob Ammerman
> > Sent: Saturday, 21 February 2004 1:17 am
> > To: PICLIST@MITVMA.MIT.EDU
> > Subject: Re: [EE:] Current Transformers
> >
> >
> > By the way, be very careful when working with a CT. If the
> > secondary ever
> > goes open circuit (ie: the burden resistor is disconnected)
> > the voltage will
> > skyrocket!
> >
> > Bob Ammerman
> > RAm Systems
> >
> > ----- Original Message -----
> > From: "Ian McLean" <ianmm@OPTUSNET.COM.AU>
> > To: <PICLIST@MITVMA.MIT.EDU>
> > Sent: Friday, February 20, 2004 7:08 AM
> > Subject: Re: [EE:] Current Transformers
> >
> >
> > > Thanks Edward,
> > >
> > > That clears things up nicely.  I am sure I can get this to
> > work now ;-)
> > >
> > > Thanks to everyone else who responded as well, and for the
> > links to CT
> > > suppliers.
> > >
> > > Rgs
> > > Ian
> > >
> > > > -----Original Message-----
> > > > From: pic microcontroller discussion list
> > > > [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Edward Gisske
> > > > Sent: Friday, 20 February 2004 6:01 pm
> > > > To: PICLIST@MITVMA.MIT.EDU
> > > > Subject: Re: [EE:] Current Transformers
> > > >
> > > >
> > > > Ian,
> > > >
> > > > Typically, you run the current carrying wire through the
> > core of the
> > > > transformer one time (sometimes a few turns). That is the
> > > > primary. The wires
> > > > coming off the CT toroid are the secondary.
> > > >
> > > > You are correct about the TVS (also known as a "Bi-Zener").
> > > > Please pardon my
> > > > acronyms. The voltage rating is selected to be low enough so
> > > > you don't blow
> > > > up whatever is downstream of the CT. A 1.5KExxx part will
> > > > soak up 1.5KW
> > > > surges without blowing up. It is unlikely you will have to
> > > > dissipate any
> > > > more than that under transient conditions, so it should
> > > > work,. The TVS is
> > > > only in action in starting or overload conditions. It is an
> > > > open circuit
> > > > under normal conditions. Think of it as two Zener diodes
> > > > wired  back-to-back
> > > > that limit AC waveforms to the breakdown voltage of the TVS.
> > > >
> > > > MOV's usually don't have a low enough turn-on voltage to be
> > > > effective for
> > > > PIC-style circuits (under 5V) so the TVS works better.
> > > >
> > > > Just put it in parallel with the burden resistor, which is in
> > > > parallel with
> > > > the CT secondary. It is a belt-and-suspenders sort of back-up
> > > > to protect the
> > > > rest of the circuit under fault conditions.
> > > >
> > > > Regards,
> > > > Edward Gisske, P.E.
> > > > Gisske Engineering
> > > > 608-523-1900
> > > > gisske@offex.com
> > > >
> > >
> > > --
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> >
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