I've used the Toroid Corporation of Maryland transformer I mentioned in the previous post driving a bridge rectifier and a burden resistor with success. As before, I like to put the resistor after the rectifier as that minimizes the effects of diode forward drops (the secondary current source forces the desired current through the burden resistor, somewhat indpendent of how much voltage it takes). Another approach I've thought of but have not tried would be to put the burden resistor right across the transformer, then run it into a PIC analog input through a current limit resistor. The PIC would half wave rectify the incoming AC. The clamp diode would remove the negative side while the A/D would read the positive. However, I've had trouble relying on clamp diodes with F series chips (I had no trouble with C chips), so I'd probably still stick with the bridge driving the resistor. The full wave rectification also gives you more samples to compute RMS from. Good luck! Harold > Resent with TAG. > > Rgs > Ian > > -----Original Message----- > From: Ian McLean [mailto:ianmm@optusnet.com.au] > Sent: Friday, 20 February 2004 4:20 am > To: 'pic microcontroller discussion list' > Subject: RE: ] Current Transformers > > > Hi all, > > Before anyone picks me up on this, I have been doing some more research on > current transformers. I don't need to rectify the secondary of the CT. > Just put a 'burden resistor' (high watts, low resistance) straight across > the secondary winding - then read the voltage across this resistor, > op-amp, > A/D input etc. > > Have I got this right ? > > Anyone know where I can get a suitable 50:5 CT from ? > > Or is there a "better way" ? > > Rgs > Ian -- http://www.piclist.com#nomail Going offline? Don't AutoReply us! email listserv@mitvma.mit.edu with SET PICList DIGEST in the body