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> Now, given an gain of 16.166666, to add 19.7 volts to the output requir=
es=0D
> adding 19.7/16.17 =3D 1.218 volts to the reference input.=0D
 =0D
Assuming Rf between Opamp's output and inverting input.=0D
Assuming Ri between Opamp's inverting input and signal input.=0D
V+ applied at the Opamp's non-inverting input=0D
 =0D
Don't forget that the gain for the non-inverting input is 1+Rf/Ri (assumi=
ng
Rf as the feedback and Ri as the input), so:=0D
V+ =3D 19.7 / (1+16.667) =3D 1.1475V=0D
=0D
I simulated this before post, seemed to work.=0D
=0D
Lucas Hartmann=20

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