-- Original Message -- From: Jinx THe bottom of the 5K pot is connected to circuit Ground. The top is connected to some voltage source, which is considered to be a = Low impedance (if it IS a voltage source). =20 The pot wiper is centered. =20 Now assume you are the A/D input looking OUT toward the pot. You see 2.5K to Ground (bottom half) and 2.5K to the Voltage Source (top = half). Because the V.S. (top) is Low-Z it can also be considered to be connected= to ground (from the viewpoint of the A/D input). So you have 2.5K in parallel with 2.5K =3D 1.25K. To: PICLIST@MITVMA.MIT.EDU Send: 2004-01-20 Subject: Re: [PIC:]18F452 A2D problem > A 5k pot gives a 1.25k source impedance How did you arrive at that ? -- http://www.piclist.com#nomail Going offline? Don't AutoReply us! email listserv@mitvma.mit.edu with SET PICList DIGEST in the body -- http://www.piclist.com hint: The list server can filter out subtopics (like ads or off topics) for you. See http://www.piclist.com/#topics -- http://www.piclist.com hint: The list server can filter out subtopics (like ads or off topics) for you. See http://www.piclist.com/#topics