First off.....yes it works, but not behaving exactly how I expected them to

Using a IR  IRLML2502 to switch 1.2V, driving the gate with +5 (direct, no
reisistor, etc)

In an equivelent circuit, each FET can be represented by the Ron, so adding
a load resistor will affect the current draw thru the device.  Since Ron is
constant, the voltage drop across the FET will change based on the loading.

So, taking some measurements, if I add a 1ohm resistor I read 1.070V across
the resistor and on the other FET seeing 1.125V (open circuit)

If I add a 0.75ohm resistor on the other part, I have two parallel circuits
that have the RDSon and the resistor.

Shouldnt the 1ohm circuit remain constant?  Or does the fact they are in
parallel now have a direct effect on it?  I sort of expect the latter since
the voltage on the 1ohm fell to 0.982 volts.

What this tells me is that voltage switching applications, unless the load
is constant (and what load is ever?) that using FETs is not really a
preferred method.

_________________________________________________________________
Let the new MSN Premium Internet Software make the most of your high-speed
experience. http://join.msn.com/?pgmarket=en-us&page=byoa/prem&ST=1

--
http://www.piclist.com hint: The list server can filter out subtopics
(like ads or off topics) for you. See http://www.piclist.com/#topics