You wrote...

>...For a Left-justified
>return the result would be 0..16368.

No, it'll be 0...65472.

>...The alternative would be
>to add a more-or-less complete set of math routines to the code, and at this
>time I don't see the need for that.

If you want to scale the input to the A/D with a voltage divider
so that the full-scale A/D result corresponds to 16.384 volts,
you hardly need a complete set of math routines: if you operate
the A/D so that its result is left-justified, just shift the
result right two bits (with zero fill) before converting it to
BCD; if you operate the A/D right-justified, shift the result
left four bits instead.

BTW, as Ken Pergola suggested, the default radix in the code I
posted was DEC.  Sorry for not specifying that.

Dave D.

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