On Sun, 14 Dec 2003 08:30:40 +1000, cdb wrote:

>Yes , I realise that it is ignoring the bank bits, I just thought it
>strange that one part of it does perform the conversion, but another
>part doesn't.
>

The instruction being 'decoded' doesn't contain the bank bits. The
program is just doing a lookup based on the information that it has
available. There's no way to be certain of the state of the bank bits
based on the binary code in the instruction. It's assuming bank 0.


Regards, Bob

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