At 10:30 PM 12/6/2003 +0000, you wrote: >I'm confused about a circuit I've been experimenting with. The circuit >is at http://www.nosreme.org/tmp/timer1b.png, using a 74HC14 hex Schmitt >trigger inverter. > >U1A (buffered by U1B) produces a low duty cycle square wave, which >slowly charges C2 through D2 and R3. So far so good. The voltage on C2 >starts to rise with the expected exponential curve, but then stops at >about 2.6V (Vcc is 5V from a 7805), and I don't understand why. I would >expect it to rise close to 5V minus a diode drop. > >I've tried the following: > >1. Disconnecting U1C, in case input leakage was causing problems - no >effect on C2. > >2. Changing C2 does change the time constant (I've tried 0.1uF and >100uF) as expected, but doesn't change the final voltage. > >3. Reducing R3 does increase the final voltage on C2, but not by very >much. With R3 around 20-30k C2 gets up to about 3V. > >I'm stumped. Can anyone enlighten me? > >The overall intention is a 4-5 minute timer (turn on, and a few minutes >later it beeps), using the first IC I happened to pick up. I already >know it's a terrible circuit. :-) What kind of diode are you using for D1, D2? Should be something like a 1N4148. If you have an oscilloscope, what is the voltage swing at pin1/2? Best regards, Spehro Pefhany --"it's the network..." "The Journey is the reward" speff@interlog.com Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com -- http://www.piclist.com#nomail Going offline? Don't AutoReply us! email listserv@mitvma.mit.edu with SET PICList DIGEST in the body