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Try  using a string, eg: "1024". And convert to a long only when the inpu=
t
is done.=0D
=0D
You could clear one digit from your long using:=0D
=0D
long v;=0D
v -=3D ((v/pow(10,n))%10)*pow(10,n); // Makes Nth digit zero;=0D
=0D
But all this calculations would take some time and space.=0D
=0D
Lucas Hartmann.=0D
 =0D
-------Mensagem original-------=0D
 =0D
De: pic microcontroller discussion list=0D
Data: Wednesday, November 12, 2003 17:02:20=0D
Para: PICLIST@MITVMA.MIT.EDU=0D
Assunto: [PIC:] LCD input and the 'long' variable=0D
 =0D
Hi all,=0D
I have a routine where the user can enter data and show the data on an lc=
d.=0D
Most of it works ok, but in the routine, but when it comes to the user=0D
entering a backspace to alter the information on the screen it all falls=0D
apart. The re-entered data gets added to the LONG and I can't find out a=0D
way of 'detecting' what decimal digit is in a certain place.=0D
 =0D
e.g. lets say the LONG is decimal 1024 and the user wants to change the '=
2'=0D
to a '3'. Accounting for powers of 10, my routine adds the 2 to the 3=0D
instead of replacing it, so it becomes 1054.=0D
 =0D
Is there any way to null that decimal character in the long integer befor=
e=0D
you add the 3 (or 30 in this case)?=0D
 =0D
Brian.=0D
 =0D
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mailto:piclist-unsubscribe-request@mitvma.mit.edu=0D
 =0D
=2E

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