jumanji wrote :

> Actually I meant something like: "one 'set' bit that rotates over 2 bytes"

OK. Doesn't change much. So you startup by putting
15 zeros and 1 one in the two bytes in some initialization
routine and then rotate all bits, right ?
The rotate code below dosn't care what's in the bytes, of course,
but rotating 16 zeros or 16 ones would be hard to debug :-)

Jan-Erik.
PS.
It should aso be said that you use the 18-series,
on the 16-series you should use RLF instead of RLCF...


> To rotate *all* bits in two bytes left :
> (bit 7 of byte 2 goes into bit 0 of byte 1 and
> bit 7 of byte 1 goes int0 byte 0 of byte 2)
>   bsf     status, c     ;Setup carry flag...
>   btfss   byte2,7       ;...according to bit 7
>   bcf     status, c     ;...of byte 2
>   rlcf    byte1         ;rotate carry into byte 1
>   rlcf    byte2         ;same for byte 2
>
> Jan-Erik.

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