Hi.

If you have to erase-before-write, and the erase
always erases 64 bytes, how would you write (or "update")
just 8 bytes if not re-writing the whole 64 byte
erased area ? If you *need* to "keep" the
rest of the 64 byte area, that is !

As I read it, in "real life", you end up writing 64
bytes (but, of course, just *one* of these bytes realy
need to have a new value.)

You *can* write 8 bytes, but only to a pre-erased
64 byte area. If you can scrap the other part
of this area, fine. Perhaps pre-erase someware
else in the code, and keep track of how much
erased space there are left ?


Jan-Erik.

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