I guess so, but you can simplify it a bit...

We know 1024 =3D=3D> 5V.
So, 157 =3D=3D> (157/1024) * 5V =3D 0.77V
0.77V / 10mV =3D 0.77V/0.01V =3D 77 deg F.

Cheers,
-Neil.


On Sunday 28 September 2003 07:32, kben@DCA.NET scribbled:
> Ok, I hooked up the LM34DZ to the PIC and received the
> output of decimal 157 from the 10 bit ADC.
>
> So, 1024/5 (Volts) is 204.8 per volt. Now the LM34DZ
> outputs 10mV per degree Farenheit, So 1V/10mv =3D 100.
> Now if I take 204.8/100 =3D 2.048. So I would divide
> my 157 from the ADC by 2.048 (Scale Factor?) to get
> degrees farenheit.
>
> Therefore 157/2.048 =3D 76 degrees F. Which agrees
> with the room temperature to within 1 degree F.
>
> Is this the correct logic for using the 10 bit ADC ?
> The answer comes out correct, I am just having a little
> difficulty grasping the concept of the conversion
> factors :)
>
> Thanks in advance,
> Kevin

---
[This E-mail scanned for viruses]

--
http://www.piclist.com hint: To leave the PICList
mailto:piclist-unsubscribe-request@mitvma.mit.edu