On Friday 12 Sep 2003 8:34 pm, you wrote:
> > I am not disagreeing with you but I still do not see why.  In a series
> > resonant circuit, the the capacitance dominates the imedance below
> > resonance and the inductor dominates above resonance.  In a parallel
> > resonant circuit the opposite is true so one might expect the shape of
> > the resonant curve to be different for these two cases.  But they can't
> > be otherwise the geometric mean would not be able to describe the
> > centre frequency in both cases.
>
> But that's the point, it's *geometric* relationship, not a linear one.
> The response of a resonant circuit is symmetric between 1/2 and 2x the
> center frequency, 1/3 and 3x, 1/10 and 10x, etc.  The response will
> therefore look symmetric on a logarithmic plot of frequency but not a
> linear one.  This is also why the geometric mean works, but a regular
> average (think of a linear mean) doesn't.
>

Maybe I am not making myself clear.  I am not disputing that it *is* this way,
what I am asking is *why* it is this way in a resonant circuit.

Ian

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