On Friday 12 Sep 2003 7:42 pm, you wrote:
> > It implies the shape of a resonant circuit is
> > different on either side of resonance and I see no reason why this
> > should be so.
>
> Actually is IS different if viewed in linear frequency space.  It is
> symmetrical in log frequency space.
>

I am not disagreeing with you but I still do not see why.  In a series
resonant circuit, the the capacitance dominates the imedance below resonance
and the inductor dominates above resonance.  In a parallel resonant circuit
the opposite is true so one might expect the shape of the resonant curve to
be different for these two cases.  But they can't be otherwise the geometric
mean would not be able to describe the centre frequency in both cases.

Ian

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